5(x^2+3y^2)-y(x^2+5y)=0

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Solution for 5(x^2+3y^2)-y(x^2+5y)=0 equation:


Simplifying
5(x2 + 3y2) + -1y(x2 + 5y) = 0
(x2 * 5 + 3y2 * 5) + -1y(x2 + 5y) = 0
(5x2 + 15y2) + -1y(x2 + 5y) = 0
5x2 + 15y2 + (x2 * -1y + 5y * -1y) = 0
5x2 + 15y2 + (-1x2y + -5y2) = 0

Reorder the terms:
5x2 + -1x2y + 15y2 + -5y2 = 0

Combine like terms: 15y2 + -5y2 = 10y2
5x2 + -1x2y + 10y2 = 0

Solving
5x2 + -1x2y + 10y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10y2' to each side of the equation.
5x2 + -1x2y + 10y2 + -10y2 = 0 + -10y2

Combine like terms: 10y2 + -10y2 = 0
5x2 + -1x2y + 0 = 0 + -10y2
5x2 + -1x2y = 0 + -10y2
Remove the zero:
5x2 + -1x2y = -10y2

Combine like terms: -10y2 + 10y2 = 0
5x2 + -1x2y + 10y2 = 0

The solution to this equation could not be determined.

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